Answer:
The needed sample size is approximately 61.46 individuals.
Explanation:
We can use the following formula to obtain the sample size:
![n_0 = \big(\frac{z_{1 - (\alpha)/(2)}S_d}{e} \big)](https://img.qammunity.org/2020/formulas/mathematics/high-school/7upzqvml770njrw3xcn8c5sf2r412q5uh0.png)
Where
is the standard deviation,
is the quantile of the normal distribution with area of
and
is the acceptable error.
![n_0 = \big((1.96*20)/(5) \big) \approx 61.46](https://img.qammunity.org/2020/formulas/mathematics/high-school/lyp13wendp2ohzff4tuomtku8bq9k7qmck.png)
We would need a sample size of 62 individuals.