Question

Place the indicated product in the proper location on the grid. Place a 0 before the decimals. (0.1x + 0.4y)2

Answer 1

`0.01x^(2) +0.08xy+0.16y^(2)`

Explanation:

For the following expression

(
`(0.1x + 0.4y)^(2)`)}

First, write the multiplication factors:

`(0.1x + 0.4y)(0.1x + 0.4y)`

Then multiply by the first term 0.1x, and later by the second term 0.4y.

You can rewrite the multiplication like this:

`(0.1x + 0.4y)\\<u>(0.1x + 0.4y)` =

`0.01x^(2) + 0.04xy`

`+0.04xy + 0.16y^(2)`

-----> Now add similar terms and you will get:

`0.01x^(2)  + 0.08xy + 0.16y^(2)`