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Place the indicated product in the proper location on the grid. (4x^3+7y^3 z^ 4) ^2

User MaxExplode
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1 Answer

5 votes

Answer:


16x^(6) +56x^(3)y^(3) z^(4) +49y^(6) z^(8) \\

Explanation:

To solve this type of problems first need to review some laws of exponents:

When you are multiplying the same base, you need to add the exponents.


x^(2) +x^(8)  = x^(2+8)  = x^(10)

When you are raising a base with power to another power, you should keep the base and multiply the exponents:


(x^(2) y^(5))^3 = x^(2*3) y^(5*3) = x^(6) y^(15)

Now for the expression
(4x^(3) + 7y^(3) z^(4) )^2

Write the multiplying factors:


(4x^(3) + 7y^(3) z^(4) )(4x^(3) + 7y^(3) z^(4) )

Multiply the term
4x^(3)


(4x^(3) + 7y^(3) z^(4) )(4x^(3) + 7y^(3) z^(4) ) = 16x^(3+3) + 28x^3y^(3) z^(4)

Then multiply the term
<strong>7y^(3)z^(4)</strong>


(4x^(3) + 7y^(3) z^(4) )(4x^(3) + 7y^(3) z^(4) ) = 16x^(3+3) + 28x^3y^(3) z^(4)\\\\<strong>+ 28x^3y^(3) z^(4) + 49y^(3+3) z^(4+4)</strong>

Simplify the exponents:


(4x^(3) + 7y^(3) z^(4) )(4x^(3) + 7y^(3) z^(4) ) = 16x^(6) + 28x^3y^(3) z^(4)\\\\+ 28x^3y^(3) z^(4) + 49y^(6) z^(8)

Add like terms:


= 16x^(6) + 56x^3y^(3) z^(4) + 49y^(6) z^(8)

User AkinKaplanoglu
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