Step-by-step explanation:
It is given that,
Let m is the mass of the object that is hung from a vertical spring of unknown spring constant k. When the spring is stretched by 17 cm, the object executes SHM. Let T is the period of oscillation that is given by :
.............(1)
The gravitational force is balanced by the force of spring at equilibrium as :
![mg=kx](https://img.qammunity.org/2020/formulas/physics/high-school/ilq7o6vnl1rqzg043wop0vtnt3iri3hx7c.png)
So, equation (1) becomes :
![T=2\pi \sqrt{(x)/(g)}](https://img.qammunity.org/2020/formulas/physics/high-school/fdp04w840upw2evsszkd06ehmw4r8artke.png)
x = 17 cm = 0.17 m
![T=2\pi \sqrt{(0.17\ m)/(9.8\ m/s^2)}](https://img.qammunity.org/2020/formulas/physics/high-school/bkh4pav6timjjj75h6ux6nkvj1nikf85v6.png)
T = 0.82 seconds
So, the period of this oscillation is 0.82 seconds. Hence, this is the required solution.