Answer: There is 2.8% of products that exhibit edge roughness.
Explanation:
Let A₁ be the event that blades are new.
Let A₂ be the event that blades are average sharpness.
Let A₃ be the event that blades are worn.
P(A₁) = 25% = 0.25
P(A₂) = 60% = 0.60
P(A₃) = 15% = 0.15
Let the B be the event that selected blade is rough.
So, P(B|A₁) = 0.01
P(B|A₂) = 0.03
P(B|A₃) = 0.05
So, P(B) would be
![P(A_1)P(B|A_1)+P(A_2)P(B|A_2)+P(A_3)P(B|A_3)\\\\=0.25* 0.01+0.60* 0.03+0.15* 0.05\\\\=0.028](https://img.qammunity.org/2020/formulas/mathematics/college/zkq640uztt2c41j86agl6ed0i1f4iiswaf.png)
Hence, there is 2.8% of products that exhibit edge roughness.