Question

What is the acceleration during the pushing-off phase, in m/27 Express your answer in meters per second squared. A bush baby, an African primate, is capable of a remarkable vertical leap. The bush baby goes into a crouch and extends its legs, pushing upward for a distance of 0.18 m. After this upward acceleration, the bush baby leaves the ground and travels upward for 2.3 m. (Figure 1) a 130 m/s All attempts used; correct answer displayed Part B Figure < 1of1 What is the acceleration during the pushing-off phase, in gs? Express your answer in terms of g Submit Provide Feedback

Answer 1

To calculate the acceleration during a vertical leap, one can use kinematic equations if the displacement and final velocity are known. In the case of the bush baby, additional data would be needed. Similar to examples in physics, where acceleration can be a multiple of g, such as 1.25 times g in a standing broad jump.

Step-by-step explanation:

To calculate the acceleration of a bush baby during its push-off phase, we must first identify the known quantities. The question mentions the bush baby leaps vertically, but it does not provide enough information to determine its acceleration directly from the push-off phase. However, we can refer to a similar example covered in physics problems. If we consider a scenario where the legs are extended by a certain distance under constant acceleration, as in the case of a standing broad jump with leg extension of 0.600 m and acceleration of 1.25 times the gravitational acceleration, g, we can use formulas from kinematics to find the result.

In general, the formula v^2 = v_0^2 + 2a(x - x_0) can be used, where v is the final velocity, v_0 is the initial velocity, a is the acceleration, and x - x_0 is the displacement. Assuming the initial velocity (v_0) is zero and the final velocity (v) is such that the bush baby just leaves the ground, we could solve for acceleration (a) if the displacement (x - x_0) during the push-off is known. Since g (gravitational acceleration) is approximately 9.8 m/s^2, the acceleration in the example would thus be 1.25 * 9.8 m/s^2.

Without the final velocity or a timeframe of the push-off phase, we can't accurately calculate the bush baby's acceleration. The acceleration during the push-off phase for given conditions has to be provided or derivable from other given data (like time or final velocity) using kinematic equations.

Answer 2

`a = 12.78 g's`

Step-by-step explanation:

Height reached by the object after push off is given as

`H = 2.3 m`

`v_f^2 - v_i^2 = 2 a s`

now we have

`0 - v^2 = 2(-9.81)(2.3)`

`v = 6.72 m/s`

now we know that this push last for total distance of 0.18 m

so during the push we will have

`v_f^2 - v_i^2 = 2 a d`

`6.72^2 - 0 = 2a(0.18)`

`a = 125.35 m/s^2`

now in terms of g = 9.81 m/s/s we have

`a = (125.35)/(9.81) gs`

`a = 12.78 g's`