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Please help me out with this!

Please help me out with this!-example-1
User Polapts
by
5.4k points

2 Answers

3 votes

Answer:

y = -8x + 12.

Explanation:

Using the slope formula: slope m = (y2-y1) / (x2-x1) where (x1,y1) and (x2,y2) are points on the line.

The slope of the line is (-68-4) / (10 - 1)

= - 72 / 9

= -8.

Now we use the slope-form of the straight line to get the required equation:

y - y1 = m(x - x1) where m is the slope and (x1, y1) is a point on the line:

y - 4 = -8(x - 1)

y = -8x + 8 + 4

y = -8x + 12. (answer).

User Avishay Bar
by
4.6k points
5 votes

Answer:

y = - 8x + 12

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (1, 4) and (x₂, y₂ ) = (10, - 68)

m =
(-68-4)/(10-1) =
(-72)/(9) = - 8, thus

y = - 8x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (1, 4), then

4 = - 8 + c ⇒ c = 4 + 8 = 12

y = - 8x + 12 ← equation of trend line

User Elliott
by
4.8k points
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