Answer:
![√(13) = D](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tjfxa32ga487a14o7ukhyoayxxh6rui8w6.png)
Explanation:
Method #1
We can draw a right triangle on the graph upon where the points are located and use the Pythagorean Theorem:
![{a}^(2) + {b}^(2) = {c}^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h2ipwfp86vksr8637t9a311u2unct0bo00.png)
![{3}^(2) + {2}^(2) = {c}^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ish6hthihnlf8b7y1frz2g6c6sv0f4u1q1.png)
![9 + 4 = {c}^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/f17lknp1jr19g7krnaewb6ytpobbu49f5c.png)
![13 = {c}^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/67em4nxspyigd2s9zwn4nhj1hayfch5u83.png)
![√(13) = c](https://img.qammunity.org/2020/formulas/mathematics/middle-school/63ck8pstbm90iyyvuo64aqlziiv7ul99nu.png)
* Whenever we talk about distance, we ONLY want the NON-NEGATIVE root.
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Method #2
We can use the Distance Formula:
![\sqrt{[-x_1 + x_2]^(2) + [-y_1 + y_2]^(2)} = D](https://img.qammunity.org/2020/formulas/mathematics/middle-school/niykja1j1yn7zcorca81ex20wguu7bn7uj.png)
N[−3, 2] M[−6, 0]
![\sqrt{[3 - 6]^(2) + [0 + 2]^(2)} = D](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cyxfwt4d1nscwr4t6wvryd4hurqe6vng4i.png)
![\sqrt{[-3]^(2) + 2^(2)} = D](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rzf4a3r69egaex2z5x7o21fnitytu0jdn0.png)
![√(9 + 4) = D](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4vzezk6n6h8zerg4jpw2ivza4kan3jtqpk.png)
![√(13) = D](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tjfxa32ga487a14o7ukhyoayxxh6rui8w6.png)
* Whenever we talk about distance, we ONLY want the NON-NEGATIVE root.
** You see? It does not matter which method you choose, as long as you are doing the work correctly.
I am delighted to assist you anytime.