Question

A 10.0g sample of H2O(l) at 23.0degrees C absorbs 209 joules of heat. What is the final temp of the H2O(l) sample? Explain.

Answer 1

Final temperature = 28.0 degrees C.

Step-by-step explanation:

heat absorbed = mass * specific heat * rise in temperature.

The specific heat of water is 4.186 J /g/C so we have the equation

209 = 10 * 4.186 * x where x is the temperature increase

41.86x = 209

= 5 degrees C.