Question

A 10.0g sample of H2O(l) at 23.0degrees C absorbs 209 joules of heat. What is the final temp of the H2O(l) sample? Explain.

Answer 1

The answer to your question is: 28°C

Step-by-step explanation:

Data

mass = 10 g

T1 = 23°C

T2 = ?

Q = 209 joules

Formula

Q = mC(T2 - T1)

T2 = Q/mC + T1

T2 = 209/(10 x 4.182) + 23

T2 = 4.99 + 23

T2 = 27.99 ≈ 28°C