Question

an eskimo pushes a loaded sled with a mass of 300kg over the frictionless surface of hard-packed snow.he exerts a constant 170n force as he dose so.what is the sled's acceleration?

Answer 1

0.567 m/s²

Step-by-step explanation:

Newton's second law:

∑F = ma

170 N = (300 kg) a

a = 0.567 m/s²

Round as needed.

Answer 2

The sled's acceleration is
`\vec{a}=0,57(m)/(s^(2))\hat{x}` .

Step-by-step explanation:

Newton's second law of motion states that in an inertial frame of reference the net force
`\vec{F}` acting on an object is equal to the mass m of the object multiplied by its acceleration
`\vec{a}`:

`\vec{F}=m\vec{a}`

`\vec{F}` and
`\vec{a}` are vectors and the mass m is a scalar that we assume to be constant. We also assume that the net force
`\vec{F}` and the acceleration
`\vec{a}` are in the horizontal direction x.

We are told that |F| = 170 N and that m = 300 kg. So we get that:

`170N=300kg\ a`

`170(kg\ m)/(s^(2))=300kg\ a`

`a=(170)/(300) (kg\ m)/(s^(2)) (1)/(kg)`

`a=0,57(m)/(s^(2))`

Then the sled's acceleration is

`\vec{a}=0,57(m)/(s^(2))\hat{x}`