Question

Find the equation of the line that contains the point ( -3, -1 ) and is parallel to the line 6x+5y=11 write the equation in slope intercept form

Answer 1

To find the equation of the line, you must first of all find the slope in the given equation,how do you do that? You just need to make y the subject of the formula and then compare the resulting equation to y = mx + c, knowing fully well that m represent the slope.

i.e from the equation 5y = 11 - 6x

y = 11/5 - 6x/5

i,e the slope is -6/5

Note: for two lines to be parallel, they must have the same slope

i.e m1 = m2

using the formula y - y1 = m ( x - x 1) to find the equation of the line

it implies : y - (-1) = -6/5 ( x - {-3})

y + 1 = -6/5 ( x +3)

multiply through by 5

5 ( y+1) = -6 ( x +3)

5y +5 = -6x - 18

5y = -6x -18-5

5y = -6x -23

To write it in slope intercept form, divide through by 5

y = -6x/5 - 23/5

Explanation: