Answer:
About 2 units.
Step-by-step explanation:
We assume that there is no heat dissipating instrument in the room
Total cooling load of the room is defined from the given below equation
=
+
+
![Q_(heat gain)](https://img.qammunity.org/2020/formulas/physics/college/eip9fj5kycjb9ncf97uxdgurwqtlr4rbh8.png)
where
= 10*100 W =1 KW
= 40*360 KJ/h= 4 KW
=15000KJ/h= 4.17 KW
= 1+4+4.17=9.17 KW
the number of air conditioner unit is =
=1.83
which is approximately 2 units