Question

In the laboratory, a student dilutes 18.2 mL of a 6.88 M perchloric acid solution to a total volume of 300. mL. What is the concentration of the diluted solution?______M

Answer 1

0.4443

Step-by-step explanation:

Considering

`Molarity_(1)* Volume_(1)=Molarity_(2)* Volume_(2)`

Given that:

`Molarity_(1)=6.88\ M`

`Volume_(1)=18.2\ mL`

Total volume = 300 mL

`Volume_(2)=300-18.2\ mL=281.8\ mL`

`Molarity_(2)=?`

So,

`6.88* 18.2=Molarity_(2)* 281.8`

`Molarity_(2)=0.4443\ M`