Question

6. STATEANSWERIN SIG FIGSOR g/cm3. What mass of silver in grams (g) would be required to cover a dimensions of 120.0 ft x 60.0 ft to a depth of 0.33 ft? SCIENTIFIC NOTATION. Silver has a densityof 10.5

Answer 1

`7.0643* 10^8 grams` of silver would be required.

Step-by-step explanation:

Dimensions of silver mas :

Length = l = 120.0 ft

breadth = b = 60.0 ft

Height = h = 0.33 ft

Volume of silver mass ,V= l × b × h

`V=120.0 ft* 60.0ft* 0.33 ft=2,376 ft^3=67,278,816 cm^3`

`1ft^3=28316.8 cm^3`

Density of silver,d =
`10.5 g/cm^3`

`Mass = Density* Volume`

`m=10.5 g/cm^3* 67,278,816 cm^3=7.0643* 10^8 g`

`7.0643* 10^8 grams` of silver would be required.