Question

Concentration of Cl ion of 72.24g NaCl in .862 L solution

Answer 1

`Molarity_(Cl^-)=1.434\ M`

Step-by-step explanation:

Moles of NaCl :

Given, Mass of NaCl = 72.24 g

Molar mass of NaCl = 58.44 g/mol

The formula for the calculation of moles is shown below:

`moles = (Mass\ taken)/(Molar\ mass)`

Thus,

`Moles= (72.24\ g)/(58.44\ g/mol)`

`Moles\ of\ NaCl= 1.2361\ mol`

NaCl is a strong salt. So, moles of chloride ion = 1.2361 moles

Volume = 0.862 L

`Molarity=(Moles\ of\ solute)/(Volume\ of\ the\ solution)`

`Molarity_(Cl^-)=(1.2361)/(0.862)`

`Molarity_(Cl^-)=1.434\ M`