Question

What is the pressure of 0.38 mol of gas if it has a volume of 9.614 L and a temperature of 255 K. The gas constant is i (Hint: don't worry about what a "pas constant" is just make the units work! This is a conversion factor do NOT plug any numbers into it. Use it to cancel units) ball Park 0.8-0.9 atm

Answer 1

The answer to your question is: P = 0.827 atm

Step-by-step explanation:

Data

n = 0.38 mol

volume = 9,614 l

temperature = 255 °K

R = 0.08206 atm L/mol°K

Formula

PV = nRT

P = nRT / V

Process

`P = ((0.38)(0.08206)((255))/((9.614))`

`P = (7.952)/(9.614)`

`P = 0.827 atm`