Question

A ball is thrown into the air with a initial velocity of 25 meters per second.The function h(t)+-4.9t^2+25t+6 represents the height of the t in seconds. ball above the ground in meters,with respect to time.at h(3) then the height of the ball would be

Answer 1

36.9 m.

Explanation:

h(t) = -4.9t^2+25t+6

At time = 3 seconds the height is h3).

h(3) = -4.9*9 + 25*3 + 6

= 36.9 m.