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You measure a small block of gold (D=19.3g/cm3) to be 2.777 inches long, 2.434 inches wide, and 1.688 inches high. What is the mass of the gold block in kg? (2.54cm=1inch exactly)

User Nese
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1 Answer

2 votes

Answer:

3.608 kg

Step-by-step explanation:

Given that:

l = 2.777 inch

b = 2.434 inch

h = 1.688 inch


Volume\ of\ the\ cube=l* b* h

Thus,


Volume_(gold)=2.777* 2.434* 1.688\ {inch}^3


Volume_(gold)=11.4095\ {inch}^3

1 inch = 2.54 cm

So,
1\ {inch}^3=({2.5})^3\ cm^3


Volume_(gold)=186.9682\ {cm}^3

Given: Density = 19.3 g/cm³


Density=\frac {Mass}{Volume}

So, Mass= density * Volume = 19.3 g/cm³ * 186.9682 cm³ = 3608.48626 g

1 g = 0.001 kg

So, Mass = 3.608 kg

User Mostafa Vatanpour
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