Question

When 8.00 g of Pb(C2H5O2)2 xH20 are heated, 1.14 g of H2O are driven off. Find the chemical formula and the name of the hydrate.

Answer 1

The formula is

Thus, moles are:

`moles= (6.86\ g)/(329.3198\ g/mol)`

`moles= 0.0208\ mol`

The moles of water is :

Amount = 1.14 g

Molar mass of
`H_2O[tex] = 18 g/mol </p><p>The formula for the calculation of moles is shown below: </p><p>[tex]moles = (Mass\ taken)/(Molar\ mass)`

Thus, moles are:

`moles= (1.14\ g)/(18\ g/mol)`

`moles= 0.0633\ mol`

The simplest ration of the two are:

[tex]Pb(C_2H_5O_2)_2:H_2O[tex] = 0.0208 : 0.0633 = 1 : 3

The formula is [tex]Pb(C_2H_5O_2)_2.3H_2O[tex]

Name = lead(II) hydrate trihydrate