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Two cars traveled equal distances in different amounts of time. car a traveled the distance in 2 h, and car b traveled the distance in 1.5 h. car b traveled 15mph faster than car a. how fast did car b travel?

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1 Answer

4 votes

Answer:

60mph

Explanation:

Let d be the distance. Let v be the speed of car a. That means the speed of car b is v + 15. Now we can set up 2 equations using the v = d/t:

Car a: v = d / 2 --> d = 2v

Car b: v + 15 = d / 1.5

We can solve for v by substituting the first equation (rearranged to isolate d) into the second:

v + 15 = 2v / 1.5

1.5v + 22.5 = 2v

0.5v = 22.5

v = 45

We're looking for the speed of car b, which was v + 15 = 45 + 15 = 60.

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