Question

At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball's acceleration is 800 m/s^2 and the vertical or y component of its acceleration is 880 m/s^2. The ball's mass is 0.37 kg. What is the magnitude of the net force acting on the soccer ball at this instant?

Answer 1

Answer:440.03 N

Step-by-step explanation:

Given

horizontal component of acceleration
`(a_x)=800 m/s^2`

vertical component of acceleration
`(a_y)=880 m/s^2`

mass of ball =0.37 kg

Force in horizontal direction
`=m* a_x=0.37* 800=296 N`

Force in vertical direction
`=m* a_y=0.37* 880=325.6 N`

Therefore net force is

`F=F_x+F_y`

`|F|=√(296^2+325.6^2)`

|F|=440.03 N