Question

A powerful motorcycle can accelerate from rest to 26.8 m/s (60 mi/h) in only 3.90 s. (a) What is its average acceleration in m/s^2? __________ m/s^2 (b) How far does it travel in that time? __________ m

Answer 1

given,

v = 26.8 m/s

t = 3.90 s

`a_(avg)=(v-u)/(t)`

`a_(avg)=(26.8-0)/(3.9)`

`a_(avg)=6.87\ m/s^2`

average acceleration is equal to
`a_(avg)=6.87\ m/s^2`

v² = u² + 2 a s

`26.8^2= 0^2 + 2* 9.8 * s`

`s = (26.8^2)/(2* 9.8)`

s = 36.64 m

distance travel at that time, s = 36.64 m