Question

A six pack of your favorite beverage (12 fl. oz. cans, assumed to have the same characteristics as water) is placed in a cooler at 70° F. How much heat must be removed (BTU) to cool the beverages to 34°F?

Answer 1

`Q = 169 BTU`

Step-by-step explanation:

As we know that volume is given as

`V = 12 Fl oz`

so it is given in liter as

`V = 12 fl oz = 0.355 Ltr`

now we have six pack of such volume

so total volume is given as

`V = 6* 0.355 Ltr`

`V = 2.13 ltr`

so its mass is given as

`m = 2.13 kg`

now the change in temperature is given as

`\Delta T = 70 - 34 = 36 ^oF`

`\Delta T = 20^oC`

now the heat given to the liquid is given as

`Q = ms\Delta T`

`Q = 2.13(4186)(20)`

`Q = 1.78 * 10^5 J`

`Q = 169 BTU`