Question

A long jumper goes into a jump at an angle of 20.0° above the horizontal and at a speed of 9.9 m/s. What is his time of flight (the time the jumper is in the air), in units of seconds?

Answer 1

T = 0.69 s

Step-by-step explanation:

given,

speed of the long jumper = 9.9 m/s

angle of the jump = 20°

time of flight calculation = ?

using equation of time of flight

`T = (2\ u \ sin \theta )/(g)`

`T = (2* 9.9 * sin 20^0)/(9.8)`

T = 0.69 s

so, the time of flight of the jumper is equal to T = 0.69 s