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A 22.5 μF spherical capacitor is composed of two metallic spheres, one having a radius twice as large as the other. If the region between the spheres is a vacuum, determine the volume of this region. ______ m^3

User Zedoo
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1 Answer

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Answer:

Volume of the sphere
=0.0347* 10^(18)m^3

Step-by-step explanation:

We have given that capacitance of spherical capacitor
C=22.5\mu F=22.5* 10^(-6)F

We have to find the volume of sphere

We know that capacitance of spherical capacitance is given by
C=4\pi \epsilon _0r

So
22.5* 10^(-6)-4* 3.14* 8.85* 10^(-12)r


r=0.2024* 10^(6)m

Now volume of sphere
V = (4)/(3)\pi r^3=(4)/(3)* 3.14* (0.2024* 10^6)^3=0.0347* 10^(18)m^3

User Ari Gold
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