Question

What is the equation of the circle with a diameter of 6 units and a center located at (2, −5) on the coordinate plane? a A b B c C d D

Answer 1

`(x-2)^2+(y+5)^2=36`

Explanation:

Recall that the equation of a circle of radius R centered at
`(x_0,y_0)` is given by:

`(x-x_0)^2+(y-y_0)^2=R^2`

For your particular case: R = 6,
`x_0` = 2, and
`y_0` = -5, therefore the equation becomes:

`(x-x_0)^2+(y-y_0)^2=R^2\\(x-2)^2+(y-(-5))^2=6^2\\(x-2)^2+(y+5)^2=36`