What is the equation of the circle with a diameter of 6 units and a center located at (2, −5) on the coordinate plane? a A b B c C d D

Question

asked Aug 28, 2020 112k views

1 Answer

Danr · Answer 1 · 2020-08-31T22:45:40+0000

Answer:

(x-2)^2+(y+5)^2=36

Explanation:

Recall that the equation of a circle of radius R centered at
(x_0,y_0) is given by:

(x-x_0)^2+(y-y_0)^2=R^2

For your particular case: R = 6,
x_0 = 2, and
y_0 = -5, therefore the equation becomes:

$(x-x_0)^2+(y-y_0)^2=R^2\\(x-2)^2+(y-(-5))^2=6^2\\(x-2)^2+(y+5)^2=36$