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X^2 (4x - 5) (7x - 13)= 0

Pleaseeee helppppp

User Froethen
by
7.1k points

1 Answer

1 vote

Answer:

see explanation

Explanation:

To solve

x²(4x - 5)(7x - 13) = 0 ← in standard form

Equate each of the factors to zero and solve for x

x² = 0 ⇒ x = 0 with multiplicity 2

4x - 5 = 0 ⇒ 4x = 5 ⇒ x =
(5)/(4)

7x - 13 = 0 ⇒ 7x = 13 ⇒ x =
(13)/(7)

User Max De Marzi
by
7.0k points