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A world record was set for the men’s 100-m dash in the 2008 Olympic Games in Beijing by Usain Bolt of Jamaica. Bolt "coasted" across the finish line with a time of 9.69 s. If we assume that Bolt accelerated for 3.00 s to reach his maximum speed, and maintained that speed for the rest of the race, calculate his maximum speed and his acceleration. (a) In your notebook, draw a sketch of the run. The 100 m-dash is made up of what two motions? Label the sketch with vectors for velocity and acceleration at the start and finish and at the end of each motion.

User Luis Lopez
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Answer:


a = 4.07 m/s^2

now his maximum speed is given as


v = 3a = 12.21 m/s

Step-by-step explanation:

Total time for which Usain Bolt accelerated is given as


t_1 = 3 s

now the velocity after uniform acceleration is given as


v_1 = 0 + 3a

now remaining time for which he run for the finish line is given as


t_2 = (9.69 - 3) = 6.69 s

now the distance moved by him during uniform acceleration is given as


d_1 = (1)/(2)a(3^2)


d_1 = 4.5 a

another distance that he moved for uniform speed is given as


d_2 = (3a)(6.69)


d_2 = 20.07 a

now total distance moved by him is 100 m so we have


20.07 a + 4.5 a = 100


a = 4.07 m/s^2

now his maximum speed is given as


v = 3a = 12.21 m/s

A world record was set for the men’s 100-m dash in the 2008 Olympic Games in Beijing-example-1
User Sound Conception
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