Answer:
![a = 4.07 m/s^2](https://img.qammunity.org/2020/formulas/physics/college/k9neun2ssl477qvsugqtg0x0qaa0d00gfl.png)
now his maximum speed is given as
![v = 3a = 12.21 m/s](https://img.qammunity.org/2020/formulas/physics/college/ft0qgsjo9yhwmmgxlonyj3niaarhc2gxu2.png)
Step-by-step explanation:
Total time for which Usain Bolt accelerated is given as
![t_1 = 3 s](https://img.qammunity.org/2020/formulas/physics/college/rd87wthzk9lw5kkr5iqlzexk15drww81bg.png)
now the velocity after uniform acceleration is given as
![v_1 = 0 + 3a](https://img.qammunity.org/2020/formulas/physics/college/v80dranbrgsei4r543ifjy8p13wekcdukh.png)
now remaining time for which he run for the finish line is given as
![t_2 = (9.69 - 3) = 6.69 s](https://img.qammunity.org/2020/formulas/physics/college/ef9z57vu8l577smwepl0e8r6bdn12aqtco.png)
now the distance moved by him during uniform acceleration is given as
![d_1 = (1)/(2)a(3^2)](https://img.qammunity.org/2020/formulas/physics/college/86a7sfzeo4fett62tduy72xxvkyccchfay.png)
![d_1 = 4.5 a](https://img.qammunity.org/2020/formulas/physics/college/p59bha0d7tktjs47smqfabe5bkqgkp8ix5.png)
another distance that he moved for uniform speed is given as
![d_2 = (3a)(6.69)](https://img.qammunity.org/2020/formulas/physics/college/wdytl5rp07p1ijldutty30ybtpm4vykrg8.png)
![d_2 = 20.07 a](https://img.qammunity.org/2020/formulas/physics/college/ip5xyopd6feempvirce29ww31vihb1ia1t.png)
now total distance moved by him is 100 m so we have
![20.07 a + 4.5 a = 100](https://img.qammunity.org/2020/formulas/physics/college/zw9898lb0ogg8j67o56hpohwf017lq753n.png)
![a = 4.07 m/s^2](https://img.qammunity.org/2020/formulas/physics/college/k9neun2ssl477qvsugqtg0x0qaa0d00gfl.png)
now his maximum speed is given as
![v = 3a = 12.21 m/s](https://img.qammunity.org/2020/formulas/physics/college/ft0qgsjo9yhwmmgxlonyj3niaarhc2gxu2.png)