Question

Suppose that the electric potential outside a living cell is higher than that inside the cell by 0.063 V. How much work is done by the electric force when a sodium ion (charge = +e) moves from the outside to the inside?

Answer 1

`W=1.008* 10^(-20)\ J`

Step-by-step explanation:

Given that

Potential difference ,ΔV= 0.063 V

Charge q

`q=1.6* 10^(-19)\ C`

The work done by electric force given as

W = ΔV . q

`W=0.063* 1.6* 10^(-19)\ J`

`W=1.008* 10^(-20)\ J`