Question

A thermos contains 144 cm^3 of coffee at 95.0 °C. To cool the coffee, you drop two 10.9-g ice cubes into the thermos. The ice cubes are initially at 0 °C and melt completely. What is the final temperature of the coffee in degrees Celsius? Treat the coffee as if it were water.

Answer 1

Answer:
`T=69.56^(\circ)`

Step-by-step explanation:

Given

volume of
`V=144 cm^3`

mass of coffee
`=\rho * volume =1* 144=144 gm`

Initial temperature of coffee
`=95^(\circ)`

mass of ice cubes =10.9 gm

and latent heat of ice=0.336 MJ

heat absorb by ice lowers coffee temperature

`m_(ice)* L=m_(coffee)* c* (95-T)`

`10.9* 0.336* 10^6=144* 4.184* (95-T)`

`336=13.21* (95-T)`

`T=69.56^(\circ)`