Question

Assume that a parent has the genotype AaBb. The A and the B genes are independently assorting. (The genotype can also be written A/a;B/b). What gametes will this AaBb individual produce?

Answer 1

AB, Ab, aB, ab

Step-by-step explanation:

According to the law of independent assortment two genes separate differently from each other during gamete formation process. This means that the gametes have equal probability of receiving each combination of the alleles.

Here, two genes "A" and "B" are present in heterozygous AaBb genotype. They assort independently of each other. So, the combinations of A and B would result into four types of gametes:

AaBb = AB

Ab

aB

ab