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If a man with one dominant gene for Huntington’s disease marries a women who has no genes for the disease, what is the probability that their child will have the disease?

a. 25%
b. 100%
c. 0%
d. 50%

User Bignum
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5.1k points

1 Answer

4 votes

Answer:

The correct answer is 50 %.

Step-by-step explanation:

Huntington’s disease has autosomal dominant inheritance. This means that the children of one parent with one dominant gene for Huntington’s disease will get the disease with a 50% chance.

User Boris Nikolaevich
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