Answer:
![{x}^(2) - x - 12 = (x + 3)(x - 4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/z3lxlucw7cpnz0t9avp0mwxz5f6rjtp2gv.png)
![{x}^(2) + 3x + 2 = (x + 2)(x + 1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7klvms9zts5udjrewcb4ds29ezs8t81iuq.png)
![{x}^(2) + 3x - 10 = (x + 5)(x - 2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/966m4gir6sbohlxighdbvk0ve0t6w25ch5.png)
Explanation:
F [First terms] - Multiply the first terms in each set of parentheses FARTHEST TO THE LEFT
O [Outside terms] - Multiply the first term in the first set of parentheses FARTHEST TO THE LEFT by the last term in the second set of parentheses FARTHEST TO THE RIGHT
I [Inside terms] - Multiply the last term in the first set of parentheses FARTHEST TO THE RIGHT by the first term in the second set of parentheses FARTHEST TO THE LEFT
L [Last terms] - Multiply the last terms in each set of parentheses FARTHEST TO THE RIGHT
![{x}^(2) - x - 12 = {x}^(2) - 4x + 3x - 12](https://img.qammunity.org/2020/formulas/mathematics/middle-school/eisxqk8qgh9143bdxkzv0poducu3irfigs.png)
![{x}^(2) + 3x + 2 = {x}^(2) + x + 2x + 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fly497pi9ulxifopon7kno6y5sfske223r.png)
![{x}^(2) + 3x - 10 = {x}^(2) - 2x + 5x - 10](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w8xi84atictnz5bfaj786wjz6ol7jysrvp.png)
I am joyous to assist you anytime.