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Write the normal form of the equation of the line passing through (1, 2) and with a normal vector n = 3 - 41. Write its general form. + Drag and drop your images or click to browse...

User Purvi
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1 Answer

5 votes

Answer:

general form of is 3x - 4y = -5

Explanation:

Equation pass through given point P (1,2)

And normal vector is given as
\begin{bmatrix}1\\ 2\end{bmatrix}

nX = np


\begin{bmatrix}3\\ -4\end{bmatrix} \begin{bmatrix}x\\ y\end{bmatrix}  =   \begin{bmatrix}3\\ -4\end{bmatrix}  \begin{bmatrix}1\\ 2\end{bmatrix}


\begin{bmatrix}3\\ -4\end{bmatrix}  \begin{bmatrix}x\\ y\end{bmatrix} = -5

therefore general form is written as ax + by = k

3x - 4y = -5

User Joe Basirico
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