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_____ 10. How many milligrams of active ingredient are required to prepare 10 mL of 0.3% (w/v) solution?

User Fragorl
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1 Answer

5 votes

Answer:

30 mg of active ingredient is required to prepare a 0.3% (W/V) solution.

Explanation:

0.3% (w/v) solution can also be expressed as: 0.3 g active ingredient for 100 ml of solution.

So:


(0.3g)/(100 ml) *(1000mg)/(1g)*10ml= 30 mg

In conclusion, we need to weigh 30 mg of active ingredient and then dilute it in 10 ml of water.

User Nikunj Peerbits
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