Question

How to solve system using elimination or substitute for A+3B-2C=20 A=5B C=2B-2?

Answer 1

i honestly dont know sorry

Explanation:

Answer 2

See the procedure.

The solution is:

`A=20\\B=4\\C=6`

Explanation:

In order to solve the system using the Substitution method, you can follow these steps:

1. Substitute the second equation
`A=5B` and the third equation
`C=2B-2` into the first equation
`A+3B-2C=20`; and then solve for "B":

`(5B )+3B-2(2B-2)=20\\\\8B-4B+4=20\\\\4B=20-4\\\\B=(16)/(4)\\\\B=4`

2. Knowing the value of "B", substitute it into the the second equation to find "A":

`A=5(4)\\\\A=20`

3. Substitute the value of "B" into the third equatio to find "C":

`C=2(4)-2\\\\C=6`