Answer:
39.77 m/s
Explanation:
We are given that
Average speed of Moe for first hour=42 mph
They stop car for gas for 10 minutes
Average speed of Joe for 40 minutes=31 mph
After traffic clear
Average speed of Joe fro half hour=60 mph
We have to find the average speed of car on his trip.
1 hour=60 minute
Total time =60+10+40+30=140 minutes
Time=
![(140)/(60)=2.33 hours](https://img.qammunity.org/2020/formulas/mathematics/high-school/v8fnmrtt2p1uodmkdfd0akvj21smez5tcr.png)
We have to find total distance
Distance covered when average speed 42 mph=
![speed* time=42\time 1=42 mi](https://img.qammunity.org/2020/formulas/mathematics/high-school/ss4emh1vg4fa5l8q7i4f3siho55mxdjbcg.png)
Distance covered when average speed 31 mph=
![31* (40)/(60)=20.67 mi](https://img.qammunity.org/2020/formulas/mathematics/high-school/1e33i3v15uo0hu7thi6ulnqznbuku38f0i.png)
Distance covered when average speed 60 mph=
![60* (30)/(60)=30 mi](https://img.qammunity.org/2020/formulas/mathematics/high-school/z2246kht479zf7bhdb62n5ehvxcszf5tlm.png)
Total distance=42+20.67+30=92.67 mi
Average speed =
![(distance)/(time)=(92.67)/(2.33)=39.77 m/s](https://img.qammunity.org/2020/formulas/mathematics/high-school/ata66r454wphv0cg8a8trcvytrx1gnak51.png)
Hence, average speed on this trip=39.77 m/s