79.7k views
1 vote
is (3,-3) a solution to the system 5x+4y=3, 2x-5y=19 need to be taught step by step please and thank you.

User Vili
by
8.0k points

2 Answers

6 votes
Basically all you’re doing is plugging in the inputs to the equations and see if they’re correct.

5(3)+4(-3)=3 this proves to be true
2(3)-5(-3)=21 not 19
User Mishadoff
by
8.4k points
7 votes

Answer:

(3,-3) is not a solution of the given system.

Solution:

The equations given in the problem are,


5x+4y=3 ----- (i)


2x-5y=19 ------------ (ii)

Now if (3,-3) is a solution of the system then both equation will satisfy by substituting the value of x as 3 and y as -3. If any of the equation does not satisfy with (3,-3) then this is not the solution i.e. the given value should satisfy both the equations to be a solution.

So, now substituting value of (x, y) as (3,-3) on equation (i) we get


5x+4y=3


5 *3 +4*(-3) = 3


15 -12 =3

Here,
3=3 --- (a) (satisfies the first equation)

Again substituting value of (x, y) as (3,-3) on equation (ii) we get


2x-5y=19


2*3-5*(-3) = 19


6+15 =19

Here,
21\\eq 19 --- (b) (does not satisfy the second equation)

From (a) and (b) we can conclude that the value (3.-3) does not satisfy the second equation. So, this is not a solution of the system.

User Ken Labso
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories