When 25.6 g
is burned, the moles of
emitted into the atmosphere is 1.80 mol
Step-by-step explanation:
The molar mass of octane
is calculated as 8(12) +18(1) = 114 g/mol.
Where atomic mass of Carbon is C=12, and Hydrogen H=1.The sample contains 25.6 g of octane, Therefore
The combustion of octane can be written as:
The mole ratio can be represented as:
= 16:2 = 8:1.
Hence, the quantity of carbon dioxide emitted is:
= 1.80 mol