Question

How many microliters of original sample are required to produce a final dilution of 10-3 in a total volume of 1,000 mL?

Answer 1

`10^(9)\ \mu L`

Step-by-step explanation:

Considering

`Molarity_(1)* Volume_(1)=Molarity_(2)* Volume_(2)`

Given that:

`Molarity_(1)=1.0\ M` (let)

`Volume_(1)=1000\ mL`

`Volume_(2)=?`

`Molarity_(2)=0.001\ M`

So,

`1.0* 1000=0.001* Volume_(2)`

Volume = 10⁶ mL

`1\ mL=10^(3)\ \mu L`

So, Volume =
`10^(9)\ \mu L`