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Find the foci of the ellipse whose equation is x^2/16+y^2/36=1

User Jack Lee
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1 Answer

4 votes

Answer:

(0, ±2√5)

Explanation:

The foci are the points on the major axis that are the length of the semimajor axis away from the co-vertices.

Here, that means their y-coordinate is ±√(36-16) = ±√20 = ±2√5.

The x-coordinate is that of the major axis, x=0.

Find the foci of the ellipse whose equation is x^2/16+y^2/36=1-example-1
User Talya S
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5.4k points