Question

How much heat is absorbed by 54g iron skillet when its temperature rises from 14°C to 28°C

Answer 1

Approximately 340.2 joules.

Step-by-step explanation:

The specific heat capacity of a substance gives the amount of heat required to raise the temperature of unit mass of that substance by unit temperature. Look up the specific heat capacity of iron in a thermodynamic data sheet.

`c(\text{Iron})\approx \rm 0.450 \; J \cdot g^(-1) \cdot {^(\circ)C}^(-1)`, where

• 
  `\rm J` (joule) is the unit for heat/energy,
• 
  `\rm g` (gram) is the unit for mass, and
• 
  `\rm ^(\circ)C}` degree celsius is the unit for temperature.

In other words, it takes approximately
`\rm 0.450\; J` of energy to raise the temperature of one gram of iron by one degree celsius.

In this question,

`\Delta T = 28 - 14 = \rm 14\;^(\circ)C}`.

Apply the equation:

`Q = c\cdot m \cdot \Delta T = \rm 0.450* 14 * 54 = 340.2\; J`.