Question

A 100.0 mL bubble of hot gases at 225 °C and 1.80 atm escapes from an

active volcano, what is the new volume of the bubble outside the volcano
where the temperature is -25 °C and the pressure is 0.80 atm?

Answer 1

The new or final volume is 112.1 mL.

Step-by-step explanation:

Given data:

Initial temperature = 225 °C (225 °C + 273.15 = 498.15 K)

Initial pressure = 1.80 atm

Initial volume = 100.0 mL

Final temperature = -25 °C (-25 °C + 273.15 = 248.15 K)

Final pressure = 0.8 atm

Final volume = ?

Formula

P₁V₁ / T₁ = P₂V₂ /T₂

Solution:

V₂ = P₁V₁. T₂ / T₁ . P₂

V₂ = 1.80 atm. 100 mL . 248.15 K / 498.15 K . 0.8 atm

V₂ = 44667 mL /398.52

V₂ = 112.1 mL