Question

A student takes some data with a cart rolling on an inclined track and produces the following set of data: From the graphs and line fit, determine the following quantities: The position of the cart at time t = 0: x0 = 0.3 m Correct: Your answer is correct. The initial velocity: v0 = 0.30 m/s Correct: Your answer is correct. The acceleration: a = 0.205 m/s2 Correct: Your answer is correct. The position at time t = 0.40 s: x(0.40 s)= 0.904 m Incorrect: Your answer is incorrect. The velocity at time t = 0.50 s: v(0.50 s)= 0.403 m/s Correct: Your answer is correct.

Answer 1

`x_f = 0.4364 m`

Step-by-step explanation:

As we know that initial velocity of the cart is given as

`v_i = 0.30 m/s`

initial position is given as

`x_i = 0.30 m`

acceleration of the cart is given as

`a = 0.205 m/s^2`

now position of the cart after t= 0.40 s is given as

`x_f = x_i + v_i t + (1)/(2)at^2`

`x_f = 0.30 + 0.30(0.40) + (1)/(2)(0.205)(0.40^2)`

`x_f = 0.4364 m`