Question

How much 3M NaOH (MW=40) can be made from 10.0mL of a 10M solution?

Answer 1

Step-by-step explanation:

The given data is as follows.

`M_(1)` = 3 M,
`V_(1)` = ?

`M_(2)` = 10 M,
`V_(2)` = 10.0 ml

Therefore, calculate the volume of given solution as follows.

`M_(1) * V_(1)` =
`M_(2) * V_(2)`

Now, putting the given values into the above formula as follows.

`M_(1) * V_(1)` =
`M_(2) * V_(2)`

`3 M * V_(1)` =
`10 M * 10.0 ml`

`V_(1)` = 33.3 ml

or, = 0.033 L (as 1 ml = 0.001 L)

Since, molarity of NaOH is given as 3 M and its volume is calculated as 33.3 ml.

Molarity =
`\frac{\text{mass of solute}}{\text{molar mass of solute}} * \frac{1}{\text{volume in L}}`

3 M =
`(mass)/(40 g/mol * 0.033 L)`

mass = 3.96 g

Therefore, we can conclude that mass of NaOH is 3.96 g.