Question

6.31 LAB: Leap year - functions A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is:

Answer 1

The code is given below in C with appropriate comments

Step-by-step explanation:

#include <stdio.h>

#include <stdbool.h>

bool ISLeapYear(int userYear)

{

// If a year is multiple of 400,

// then it is a leap year

if (userYear % 400 == 0)

return true;

// Else If a year is multiple of 100,

// then it is not a leap year

if (userYear % 100 == 0)

return false;

// Else If a year is multiple of 4,

// then it is a leap year

if (userYear % 4 == 0)

return true;

return false;

}

int main(void) {

int year;

printf("Enter year : ");

scanf("%d",&year);

if(ISLeapYear(year)){

printf("%d is a leap year.",year);

}else{

printf("%d is not a leap year.",year);

}

return 0;