Answer:
The driver can avoid the child because at the time she brake 1.6s the car just move 20.928 meters so is far to the 65 meters where the kind is
Distance= 20.928 m
Step-by-step explanation:
![V_(o) = 17 (m)/(s) \\a= -4.9 (m)/(s^(2) )\\ t= 1.6 s](https://img.qammunity.org/2020/formulas/physics/high-school/cn7f4cio1nl6lzvwt698tfcj5vlienh36u.png)
Distance the kid is 65m so the car have to be less in the time she is braking
So to calculated the distance while she is braking
![X_(f) = X_(o) +V_(o)*t + (1)/(2) * a *t^(2)\\ X_(f) = 0m +17 (m)/(s) *1.6 s + (1)/(2) * 4.9 (m)/(s^(2) ) *(1.6s)^(2)\\X_(f) = 27.2 m+ (-6.272 m)\\X_(f) = 20.928 m](https://img.qammunity.org/2020/formulas/physics/high-school/mvxacg48e2virzgi9tk24tb0jtfqemnq58.png)
The distance of the car is less than the distance of the kid in his bike
So she didn't hit him