Question

Equation of the line slope with slope -3 and the passes through (2,-1)

Answer 1

The equation of the line with slope -3 and passes through (2,-1) is y = -3x + 5

Solution:

In the question it is given that the line passes through the point (2,-1) with slope (m) = -3. We have to find out the point slope form and slope intercept form of the equation.

We know the point - slope form of an equation is given by

`\left(y-y_(1)\right)=\mathrm{m}\left(x-x_(1)\right)`

`\text { Here } y_(1)=-1 \text { and } x_(1)=2 \text { and the slope } m=-3`

Substituting the values in the point slope form of the equation we get

(y-(-1)) = -3(x-2)

(y+1) = -3 (x-2) is the point slope form of given line

We know the slope intercept form of a line is given by

y = mx +c

Here y = -1 , x = 2 and m = -3

Substituting the values in slope intercept form equation we get

-1 = (-3)2 + c

⇒-1 = -6 + c

⇒-1+6 = c

c = 5

Thus the slope intercept form of equation is y = -3x+5