Question

Question (1 point) 1st attempt The spectrum of a blackbody has a peak wavelength of 6.90x10 7 meters. What is its temperature,in kelvins?

Answer 1

4202.8985 K

Step-by-step explanation:

Using Wien's displacement law which states that the temperature and the wavelength of the blackbody radiation are inversely proportional.

So,

λmax= b/T

Where,

λmax is the peak of wavelength
`6.90* 10^(-7)\ m`

b is the Wien's displacement constant having value as
`2.9* 10^(-3)\  m K`

T is the Absolute Temperature in Kelvin.s

So,

T = b/λmax =
`(2.9* 10^(-3))/(6.90* 10^(-7))` = 4202.8985 K